Chapter 5 True Or False and Multiple Choice Problems 1 For each of the following ten statements answer TRUE or FALSE as appropriate (a) If f is di↵erentiable on 1,1 then fSin2(x) cos2(x) = 1 tan 2(x) 1 = sec (x) DoubleAngle Formulas sin(2x) = 2sin(x)cos(x) cos(2x) = cos2(x) sin2(x) cos(2x) = 1 2sin2(x) cos(2x) = 2cos2(x) 1 1 1(12 points) Determine whether each of the following statements is True or False True False Solution False If f(x) = 1 2x, then fsatis es that 0 f(x) < 1 x for all x 1, but Z 1Question The trigonometric function tan 8 In terms of sec @ In the ill quadrant is vi100 False Determine whether the statement is True or False 5 poin 2x' 5x2, 2x* x =1 Consider x>1 3x2 7x2 3x² x True False Determine whether the statement is True or False 5 points An equation of the line passing through the point (1,1) and
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Tan 2x sec 2x 1 true or false
Tan 2x sec 2x 1 true or false-For all values of x 2) cos2a=2cos^2a1 for ALL values of a 1) False, 1 tan 2 x = sec 2 x 2) True 3) True Upvote Students can solve NCERT Class 12 Maths Integrals MCQs Pdf with Answers to know their preparation level 1 Given ∫ 2 x dx = f (x) C, then f (x) is 2 3 5 6 If ∫ sec² (7 – 4x)dx = a tan (7 – 4x) C, then value of a is 7
Tan 1 p tan 2 1 sec2 d = Z tan 1 p sec sec2 d Remember to think carefully about the p sec2 part From here we can proceed as normal (assuming sec is positive, just for simplicity) = Z tan 1 sec sec2 d = Z tan sec sec d And we've successfully reduced the problem to an integral we can do Ivan Khatchatourian MAT137 1 February, 18 7 / 31The Pythagorean identity sin^2(x)cos^2(x)= 1 is useful in proving the identity tan(x)sec(x)= (cos(x)/(1sin(x))) true or false Answer by stanbon(757) ( Show Source ) sin^2 (x) cos^2 (x) = 1 everywhere An alternate approach to proving this identity involves using the "unit circle" (radius = 1) Since the radius is
It is a trignometrical identity, there is nothing there to solve The identity is arrived at by simplifying the identities in sin(x y) cos(x y) = sinxcosy cosxsiny cosxcosy − sinxsiny Divide the numerator as well as the denominator by cos x cosy to get tanx tany 1 − tanxtany Answer link 1 = (sec(x)) 2 (tan(x)) 2 Now, we will see if 1 = (sec(x)) 2 (tan(x)) 2 and 1 = (sec(x)) 2 (tan(x)) 2 can both be true We can do this by assuming that they are both true, and then add the equations to get Tan^2 x1=sec^2x So to get 1 on the other side of the equal sign wouldn't it be sec^2xtan^2x=1?Get stepbystep solutions from expert tutors as fast as 1530 minutes Your first 5 questions are on us!1 A water molecule is held together by two single polar covalent bonds False 2 Because oxygen has a greater electronegativity than hydrogen, water molecules are polar with Biology These are true and false questions and I want to make sure that I got them right 1
tan^2x sin^2x (sec^2x 1)(1cos^2x) sec^2x 1 1 cos^2x 1/cos^2x 2 cos^2x (1/cosx cosx)^2 God luck with that Or use your doubleangle formula a couple of times tan^2x sin^2x cos^2x = (1 cos2x)/2 sin^2x = (1 cos2x)/2 You wind up with (cos4x 4cos2x 3) / 4(cos2x 1) Use your halfangle formulas for the other oneFind the second order derivatives of the following e2x tan x Mathematics and StatisticsHere f = cos 2 x and g = tan x To differentiate f, we need to use chain rule \(\frac{d}{dx}\) (cos 2 x tan x) = tan x\(\frac{d}{dx}\) (cos 2 x) cos 2 x\(\frac{d}{dx}\) (tan x) \(\frac{d}{dx}\) (e x tanx) = tan x(2 cos x sin x) cos 2 xsec 2 x At x = 1 we get, = tan0(2 cos 0 sin 0) cos 2
= sin x cos x sin 2 x cos 2 x We know that sin 2 x cos 2 x = 1 Therefore, = sin x c o s x 1 = sec x cosec x Hence, proved We have, = sec 2 x c o s e c 2 x = cos 2 x 1 sin 2 x 1 = sin 2 x cos 2 x sin 2 x cos 2 x = sin 2 x cos 2 x 1 = sec 2 x c o s e c 2 x Hence, proved Since ≠ for all values of the equation is not an identity x − 2 x 1 sec 4 sec 2 x tan 2 x cot 2 x − 2 x 1 sec 4 sec 2 x tan 2 = (x −1)(x −1) sec 2 sec 2 x tan 2 = x ⋅ x tan 2 tan 2 x tan 2 x tan 2 x − 1 sec 2 = x tan 2 x tan 2 x cot 2 x, Page 1 of 12 PRACTICE TEST 61 tan^2xsec^2x=1 true or false?
Get stepbystep solutions from expert tutors as fast as 1530 minutes Your first 5 questions are on us!True or False On the scan form A = true and B = false (1 pt each) 1 Given x > 0, d dx tan x = sec2 x 2 Given y > 0, tan y = sec2 y 3 ln e = 0 4 log 7 x = 1 x 5 The derivative of f(x) = 7x is f ' (x) = (x)7 x1 6 cos1 x is equal to 2 1 1x 7 The derivative of f(x) = csc 2x is f ' (x) = – csc 2x cot 2x 8 The derivative of f(xApply the reciprocal identity to sec(x) sec ( x) Combine sin(x) sin ( x) and 1 cos(x) 1 cos ( x) Rewrite sin(x) cos(x) sin ( x) cos ( x) as tan(x) tan ( x) Because the two sides have been shown to be equivalent, the equation is an identity
Trigonometry Q&A Library Verify the identity 1 sec 0 tan e =2 cot 0 tan 0 1 sec 0 To verify the identity, start with the more complicated side and transform it to look like the other side Choose the correct transformations and transform the expression at each step 1 sec 0 tan 0 tan 0 1 sec 0 (Do not simplify)False Take \(f(x)=1\) and \(g(x)=2\text{}\) True False Apply the Mean Value Theorem False Apply the chain rule False False True True The limit equals \(g'(2)\text{}\) False True \(\tan ^2x\sec ^2 x=1\text{}\) False \(\ds y=x^2x\) is not differentiable for all real numbers False False False Take \(\ds \lim _{x\to 5}\frac{x5}{x5}\text{}\) FalseThe formula sin^(1){2xsqrt(1x^(2))}=2 sin^(1) x is true for all values of x lying in the interval Let F(x) be an indefinite integral of sin^(2)x Statement1 The function F(x) satisfies F(xpi)=F(x)
Thus, the required derivative is {eq}\bf{\dfrac{2\tan(x)\arctan(2x) \sec^2(x)(14x^2)}{\tan^2(x)(14x^2)}} {/eq} Become a member and unlock all Study Answers Try it riskfree for 30 days Free PDF Download of CBSE Maths Multiple Choice Questions for Class 12 with Answers Chapter 2 Inverse Trigonometric Functions Maths MCQs for Class 12 Chapter Wise with Answers PDF Download was Prepared Based on Latest Exam Pattern Students can solve NCERT Class 12 Maths Inverse Trigonometric Functions MCQs Pdf with Answers to know theirAnswer the following questions TRUE or False If f has a vertical asymptote at x = 1 then lim x → 1f(x) = L, where L is a finite value If has domain 0, ∞) and has no horizontal asymptotes, then limx → ∞f(x) = ± ∞ If g(x) = x2 then lim x → 2 g(x) − g(2) x − 2 = 0
Determine if the following equation is true or false {eq}tan^2(x) 1=sec^2(x) {/eq} Trigonometric Identities The trigonometric identities are tools that we can use not just to simplify anIf x sin 3 θ y cos 3 θ = sin θ cos θ and x sin θ = y cos θ, prove that x 2 y 2 = 1 View Answer If tan θ = 3 − 2 , find sin 2 θ sec 2 θ − c o s 2 θ(tan x csc 2 x tan x sec 2 x) (1 tan x 1 cot x) For the following exercises, determine whether the identity is true or false If false, find an appropriate equivalent expression 40
1/(x y) = 1/x 1/y answer choices True False s Question 10 sec x tan x sec 2 x sin x arctan x s Question 27 SURVEY 30 seconds Report an issue Q Differentiate y = (x 3 1) 100 answer choices 300x 2 (x 3 1) 99 99(x 3 1) 98 100(x 3 1) 99 100(3x 2) 99 s Question 28 SURVEY 30The functions sine, cosine and tangent of an angle are sometimes referred to as the primary or basic trigonometric functions The remaining trigonometric functions secant (sec), cosecant (csc), and cotangent (cot) are defined as the reciprocal functions ofTrue or false 4)Graph of f(x) = cosec(x) has 2 vertical asymptotes in one period true or false 5)The amplitude for f(x) = 3sec(4x) is 3 true or false 6)f(x) = 2 sec(2xπ) has A Period =
Find the exact value of sin(a b) il sin(a) = and B in quadrant I 5 Solve the equation cos(2x) sind(x) = 0 over the interval 01) 6 Evaluate the expression without using a calculator cos (tan 3 – sin) 7 If sec(a) = 17,0° SaFor the following problems, consider radioactive dating A human skeleton is found in an archeological dig Carbon dating is implemented to determine how old the skeleton is by using the equation latexy=e^{rt}/latex, where latexy/latex is the percentage of radiocarbon still present in the material, latext/latex is the number of years passed, and latexr=/latex isF~(x,y) = (2x2y, 2x2y) A potential function is just a function f such that F~ = ∇f SOLUTION There are several ways to go about finding a potential function The organized antidifferentiation method is as follows If ∇f = F~ we must have fx = 2x2y (1) fy = 2x2y (2) Starting with Equation 1 and integrating with respect to x (treat
Tan^2 (2x) 1cos (6x)= 2sin^2 (3x) (true or false) sin (75 degrees)=sqrt (1cos (150 degrees)/2) true (TRUE or FALSE) The horizontal distance, in feet, traveled by a projectile can be modeled by the equation h = ( (v0^2)/16) sinθcosθ where θ is the initial angle and v0 is the initial velocityExtensions For the exercises 3439, prove or disprove the identity 34) \(\dfrac{1}{1\cos x}\dfrac{1}{1\cos (x)}=2\cot x\csc x\) 35) \(\csc^2x(1\sin^2x)=\cot^2x\) True or false The equation csc^2x1=cot^2x is an identity
Tan 1(2x) dx= xtan 1(2x) 1 4 lnj1 4x2j Cusing IBP R e 1 x3x1 x dx= (e3 1)=3 eby dividing rst and ln(e) = 1, etc lim n!1cos(2ˇn) = 1 because cos(2ˇn) = cos(0) = 1 P 1 k=1 (1 2 1 3) = 1 3, telescoping (write out a few terms) R tan3(2x)sec(2x) dx= sec 3(2x) 6 sec(2x) 2 Cusing u= sec(2xMathematics Multiple Choice Questions on "Derivatives" 1 Find the derivative of e x 2 a) e x 2 b) 2x c) 2e x 2 d) 2xe x 2 Answer d Clarification We apply chain ruleTrigonometric Identities Solver \square!
Find an expression equivalent to cos theta/sin theta tan theta cot theta ~ sec theta csc theta 3) cos 3x / cos x = 2 3 1 cos x/ sin x= sin x/ 1 cos x 4 2 sin x cos ^2 (x/2) 1/x sin (2x) = sinx 5 cos 2 x sin x/ 1 sin x= 1 2 Math sin x multiply by csc x= 1 true or false?Csc 2 x sec 2 x sin 2 x 1 sin 2 x s Report QuizMath Cheat Sheet for Integrals \mathrm{If\exist\b,\a\lt\b\lt\c,\and}\f\left(b\right)=\mathrm{undefined},
Sin x * csc x=1 is true this is because sin=oppositeQ True or false sin 2 θ = (sin θ) 2 answer choices True False s 4/5 π 4/3 π s Question 9 SURVEY 180 seconds Q tan 600 answer choices 21/2√3√3/2 s Question 10 SURVEY 30 seconds Q Which graph does NOT pass the vertical line test? \(x≥−\frac{3}{2},\quad f^{−1}(x)=−\frac{3}{2}\frac{1}{2}\sqrt{4y−7}\) 21) A car is racing along a circular track with diameter of 1 mi A trainer standing in the center of the circle marks his progress every 5 sec After 5 sec, the trainer has to turn 55° to keep up with the car How fast is the car traveling?
(Solved)State whether the following is true or false by differentiation int sin^2 x dx = dfrac{1}{2}x – dfrac{1}{4}sin(2x) C View Answer business Leave a comment Question(true or false) The value 3pi/4 is a solution for the equation 3(sqrt 2) cos theta 2 = 1 true (true or false) The value 5pi/2 is a solution for the equation 2sin^2xsinx1=0
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